Question

Factor completely:

4x^2-8xy-3x+6y

Answer 1

\(\huge\color{blue}{ \sf 4x^2-8xy-3x+6y}\)


\(\huge\color{blue}{ \sf 4x(x-2y)-3(x-2y)}\)


can you do the last step?

Answer 2

(4x-3)(x-2y)
4x-3=0
4x=3
x-3/4

x-2y=0
this is the one I'm stuck on????

Answer 3

you are solving \(\color{blue}{ \sf 4x^2-8xy-3x+6y=0 }\)


\(\color{blue}{ \sf 1 }\) equation \(\color{blue}{ \sf 2}\) unknown variables ?

Answer 4

I have to have 2 answers and the x-2y=0 is how I'm suppose to get my second answer, but i don't know how to solve it.

Answer 5

you can't solve 1 equation with 2 unknown variables !

Answer 6

oh ok thank you!

Answer 7

You welcome !