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Can someone help me solve this using the quadratic formula? x^2+3=9x
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i would like to be walked thorugh it
do you know how to complete the square?
Really, walphramalpha for this? Even I can do it with my OWN head
First subtract 9x from both sides so that you have: \[x^2-9x+3=0\]
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Now notice that a = 1, b = -9 and c = 3 Plugging into the formula, we have: \[x=\frac{9\pm \sqrt{81-4(1)(3)}}{2}\]
Perhaps you can simplify that on your own.
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