Question

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Answer 1

Just need to find X... a little confused

Answer 2

@ganeshie8

Answer 3

2x^2 + 12x + 3 = 0

this is a quadratic equation, to find x intercepts you simply set the equation to 0 and solve for x as above,

you can plug this into the quadratic equation to find the values of x, which are:

x1=−3+(1/2(sqrt30))
x2=−3−(1/2(sqrt30))

Answer 4

y=2x^2+12x+3
x_intercect is the x values when y =0

Answer 5

let
a=2
b=12
c=3
use the general formula
\(\Huge\color{green}{x= \frac{-b \pm \sqrt{b^2-4ac } }{2c}}\)