Question

help

Answer 1

\[6\sqrt{35}-2\]

Answer 2

@ganeshie8 @ikram002p Can either of you verify?

Answer 3

@Luigi0210 @sourwing @whpalmer4

Answer 4

a+b(c+d)

Answer 5

a(c+d)+b(c+d)

Answer 6

Is my answer correct?

Answer 7

just try using this formula @vshiroky

Answer 8

I did use that formula.. I'm just trying to double check

Answer 9

where's ur ans

Answer 10

Above the 6sqrt35-2

Answer 11

\[6sqrt{35-2}\] u mean this?

Answer 12

yes

Answer 13

doesnt look correct,
u knw about FOIL ?

Answer 14

-2+6sqrt35

Answer 15

its not correct

Answer 16

11-9sqrt35

Answer 17

There you go...

Answer 18

\(\large \color{red}{\checkmark}\)

Answer 19

\[5sqrt{5(sqrt{5-2sqrt{7}}}) +sqrt{7}(sqrt{5-2sqrt{7}})\]

Answer 20

My way:

let \(s = \sqrt{7}\) and \(f = \sqrt{5}\)
\[(5f+s)(f-2s) = 5f^2 -10sf +sf -2s^2\]\[=5(\sqrt{5})^2 - 10\sqrt{5}\sqrt{7} + \sqrt{5}\sqrt{7} - 2(\sqrt{7})^2\]\[=25-9\sqrt{35}-14\]\[ = 11-9\sqrt{35}\]

Answer 21

any problem with lots of messy algebra involving radicals or trig functions, I'll probably do a substitution to make the writing or typing easier