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If f(x) = log2 (x + 4), what is f−1(3)?
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NOTE: The 2 is small towards the bottom, next to log. The -1 is small and positioned like an exponent after f.
let y=f(x) then we have y=log2 (x + 4) to find y-1 we replace x by y and y by x ---> x=log2 (y + 4) and solve for y do you know how to solve for y here ?
to multiply 2 and 4?
\[\log _{a}b = x \rightarrow 2^{x} = b\]
\[a ^{x}=b\] @iPwnBunnies
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^^ Right. I didn't mean to giveaway the answer. D:
\[\log _{a}b = x \rightarrow a^{x} = b\]
lol @iPwnBunnies @mathhelpnow can you use this identity here ?
I'll try, 2 is a, and 4 is b, right?
(y+4) would be b.
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