Question

MEDAL find the zeros of the function.
f(x)=x^3-4x^2+x+6

Answer 1

0=0

Answer 2

None of the choices are that?

Answer 3

3 , -1 &2

Answer 4

x^3-3x^2-x^2+x+6
=x^2(x-3)-(x^2-x-6)
=x^2(x-3)-(x^2-3x+2x-6)
=x^2(x-3)-(x(x-3)+2(x-3))
=x^2(x-3)-(x-3)(x+2)
=(x-3)(x^2-x-2)
=(x-3)(x^2-2x+x-2)
=(x-3)(x(x-2)+1(x-2))
=(x-3)(x-2)(x+1)

Answer 5

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