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Mathematics 11 Online
OpenStudy (anonymous):

translate and solve. the absolute value of four times the quantity of p minus 2 is less than or equal to 4. how do i solve this?

OpenStudy (anonymous):

Ill help you translate: "four times the quantity of p" = 4p "four times the quantity of p minus 2" = 4p - 2 "the absolute value of four times the quantity of p minus 2" = |4p - 2| "the absolute value of four times the quantity of p minus 2 is less than or equal to 4" = \[|4p - 2| \le 4\] Can u take it from there?

OpenStudy (anonymous):

thanks but i dont know how to solve it either

OpenStudy (anonymous):

well i tried and my answer was 1.5 but that doesnt seem right?

OpenStudy (anonymous):

Do you know that the "absolute value" (also called the "modulus") means? One way to think of it is: "the distance between 4p and 2 is \[\le 4\] So 4p is one of the numbers which are within 4 units of the number 2 Which numbers are within 4 units of the number 2?

OpenStudy (anonymous):

i dont get it

OpenStudy (anonymous):

i did it again and got the same answer 1.5

OpenStudy (anonymous):

is that the right answer?

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