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HELP PLEASE MEDAL AND FAN Given the arithmetic sequence -6, 1, 8., evaluate
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\[\sum_{4}^{9}an=\sum_{1}^{9}an-\sum_{1}^{3}an=S9-S3\] a=-6 c.d d=1-(-6)=1+6=7 \[Sn=\frac{ n }{ 2 }\left\{ 2a+\left( n-1 \right)d \right\}\]
\[S3=\sum~ of~ first~ three~ terms=-6+1+8=3\] by formula \[S3=\frac{ 3 }{ 2 }\left\{ 2*-6+(3-1)7 \right\}=\frac{ 3 }{2 }\left\{ -12+14 \right\}=\frac{ 3 }{ 2 }*2=3\] can you find S9 by the formula? here n=9,a=-6,d=7
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