If a basketball shot is made from 6ft off the ground with an initial velocity of 32 ft per second, write a quadratic equation to represent the path of the ball. Please help! Thank you! (:

Question

anonymous · Answer

Than the guy is a pro

jdoe0001 · Answer

$\bf \text{initial velocity}\
h = -16t^2+v_ot+h_o \qquad \text{in feet}\
\ \quad \

v_o=\textit{initial velocity of the object}\
h_o=\textit{initial height of the object}\
h=\textit{height of the object at "t" seconds}$