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What are the coordinates of the vertex of the graph of y= x^2+6x-11? A) (3, -2) B) (3, 16) C) (-3, -29) D) (-3, -20)
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The x-coordinate 0f the vertex( or the axis of the parabola) x = -b/2a = -6/2 = -3 The y-coordinate of the vertex: y(3) = (-3)^2 + 6(-3) - 11 = .......
@thu1935 -20?
try again
y(3) = (-3)^2 + 6(-3) - 11 = 9 - 18 - 11
simplify
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nvm, -20 is right
good job :)
ok. thanks @ganeshie8!
u wlc !!
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