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Find the value of x so that the line passing through the points will have the given slope: (x, 6) and (10, -3) with a slope of -3/2. A. -13 B. 4 C. 13 D. -12
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using the slope equation (y2-y1)/(x2-x1) = slope (-3-6)/(10-x) = -3/2 -9/10-x=-3/2 Cross Multiply -9*2=-3(10-x) -18=-30+3x -18+30=3x 3x=12 Divide by 3 both side x=4
thank you so much! :)
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