Two bus drivers , A and B , return to bus terminal every 50 and 140 minutes respectively . If they leave the bus terminal at 0630 , when will they next meet at bus terminal .

I understand it but i got 1710 h but the answer sheet wrote1100h . Please helppp!!

Question

Two bus drivers , A and B , return to bus terminal every 50 and 140 minutes respectively . If they leave the bus terminal at 0630 , when will they next meet at bus terminal . 

I understand it but i got 1710 h but the answer sheet wrote1100h . Please helppp!!

anonymous · Answer

This is a least common multiple problem
Find the LCM of 50 and 140 and that will be your answer.
Do you need assistance finding the LCM of 50 and 140 ?

anonymous · Answer

Rather that will be the number of minutes after 0630 that they will meet in the terminal..Then you just add that time to 0630 to get your answer.

anonymous · Answer

the least common multiple is 700 . isn't it?

anonymous · Answer

50=2x5^2 140=2^2x5x7 
2^2x5^2x7=700

anonymous · Answer

yeah... 700 = 60*11 + 40  so that's 11 hours and 40 min
0630 + 11 hours 40 min = 1730 + 40 min = 1810

anonymous · Answer

oh yah . thank you . So the answer will be 1810 and not 1100 right ?

anonymous · Answer

yes.