Question

Select the equations that are parallel and perpendicular to y = 2x - 1 and that pass through the point (4, 1).

parallel: y = 2x - 7
perpendicular: y = negative one over twox + 3

parallel: y = 2x + 2
perpendicular: y = negative one over twox + four and one half

parallel: y = negative one over twox - 7
perpendicular: y = 2x + 3

parallel: y = -2x - 7
perpendicular: y = negative one over two x - 1

Answer 1

If y=mx+c line parallel to this line is y=mx+c1,find c1 from this eq. by the given point and substitute in this eq.
slope of line perpendicular to y=mx+c is -1/m
Hence line perpendicular to y=mx+c is
y=(-1/m)x+c2,find c2 by the given condition and substitute in this eq.

Answer 2

I'm so confused

Answer 3

Parallel lines have equal slope.

Perpendicular lines have a negative reciprocal of = -1

Select the equations that are parallel and perpendicular to y = 2x - 1 and that pass through the point (4, 1).
Point:(4,1) y= 2x-1
m(slope) = 2

1- point slope formula= y-y1=m(x-x1)
y-1= 2 (x-4)
y-1=2x-8
y=2x-8+1
y=2x-7

Parallel: y = 2x - 7 This is parallel = the slope is 2, the same as the equation. but it has the same y- intercept so basically is the same line.
Perpendicular: y = -1/2x + 3 m= -1/2 -1/2 : 2= -2/2 = -1
This one is perpendicular and it has a different y-intercept.

Parallel: y = 2x + 2 This one has the same slope =2. And different y-intercept.
Perpendicular: y = -1/2x + 4.5 This one is perpendicular. This is your answer.


Parallel: y = negative one over twox - 7
Perpendicular: y = 2x + 3 Not perpendicular, the reciprocal of 2 : 2 = 1 not -1.

Parallel: y = -2x - 7 Not parallel, it doesn't have the same slope.
Perpendicular: y = -1/2x - 1