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Solve the following with a system of your choice 4x + 5y = 13 3x +y = -4
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solve the equations simultaneously
What you mean?
multiply 3x+y by 5
5 (3x+y)
then subtract it from the first equation
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sorry multiply 3x+y=-4 by 5
-20
15x+5y=-20
subtract 15x+5y=-20 from 4x+5y=13
-11x=33
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x=-3
Wait
substitute the value of x in the equation
-9+y=-4 y=5
How did you get -9 + y = -4
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x=-3 substitute the value of x in the second equation we get -9+y=-4
What do we do after that
we get y=5
y=-4+9 y=5
Alright. can you help in in some other problems
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okay
fixin to post it
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