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Which of the following is another form of the equation 8^(2x-1)=32 A. 4^(2x-1)=8 B. 2^(6x-3)=2^5 C.4^(4x-1)=4^8 D. 1^(2x-1)=4
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\[8^{2x-1} = (2*2*2)^{2x-1}\]
\[2^5=2*2*2*2*2\]
all u do is reduce everything
2^(6x-3)=2^5
\[(ab)^n = a^nb^n\]
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