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lim [a^x sin(b/a^x)], when a>1 is = ? x->infinity
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\[\lim_{x \rightarrow \infty} \frac{ a^x*\sin(\frac{ b }{ a^x } )}{ }\]
u knw sinx/x when limit x ....>0 ????
\[\lim_{x \rightarrow \infty} \frac{ \sin \frac{ b }{ a^x } }{ \frac{ 1 }{ a^x} }\]
multiply and divide by b
\[\lim_{x \rightarrow \infty} \frac{ b*\sin(\frac{ b }{ a^x }) }{ b*\frac{ 1 }{ a^x }}\]
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=b
Thank you very much
here 1/x is there so as x goex to infinity so it will 1/infinity=0 finally and comes to sin0/0 so we can apply lim x...>0 sinx/x
Yes, I got it. Thanks once again.
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