Question

write in standard form. determine the value of a,b,c
x^2+13x-4=14x+1
a= b= c=
Give me some solution on how to solve this problem. please

Answer 1

\[\huge x^2+13x-4=14x+1 \]
\[\huge \rightarrow x^2+13x-4-14x-1 =0\]
\[\huge \rightarrow x^2-x-5 =0\] is the standard form;
comparing it with \[\huge \rightarrow ax^2+bx+c =0\] we find:
a= 1, b= -1, c= -5

Answer 2

@candyhuebner

Answer 3

thank you for helping me