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(3x-8)(2x+1)= a 6x^2+88 b 6x^2-128 c 6x^2+28 d none of the above
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distribute 3x and -8 over the second bracket and simplify i'll start you off: (3x - 8)( 2x + 1) = 3x*2x + 3x*1 -8*2x -8*1
then my answer is 6x^2 - 15x -8 , so my answer is D
right
it doesn't make a difference to your answer but the middle term should be -13x
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