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(2x+y)^2 How do you solve this?
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\(\bf (2x+y)^2\implies (2x+y)(2x+y)\) FOIL
\[(2x+y)^{2} = 4x ^{2}+y ^{2} + 4xy\]
\[(a+b)^{2}= a ^{2}+b ^{2}+2ab\]
(2x + y)^2 = (2x + y)(2x + y) = 4x^2 + 2xy + 2xy + y^2 (combine like terms) 4x^2 + 4xy + y^2
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