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Mathematics 13 Online
OpenStudy (anonymous):

trigonometry question(Click for the Question)

OpenStudy (anonymous):

\[\tan \theta + \cot \theta = 2 \] Find the value of :- \[\tan ^{2}\theta + \cot ^{2}\]

OpenStudy (anonymous):

Hint: try squaring both sides

OpenStudy (anonymous):

^

OpenStudy (anonymous):

Do u mean (tan x + cot x )^2 ?/

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Nope i don't think so

OpenStudy (anonymous):

Beacause (tan x + cot x )^2 = tan^2 x + 2 tanx . cot x + cot^2 x

OpenStudy (anonymous):

(a+b)^2 types

OpenStudy (anonymous):

Oh I compeletly forgot

OpenStudy (anonymous):

disregard me lol

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

well (tanx)(cotanx)= 1

OpenStudy (anonymous):

That is actually what i mean, look at 2 tanx . cotx closely, you may notice something :)

OpenStudy (anonymous):

so 2 is the answer

myininaya (myininaya):

did you square both sides yet @openstudier

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i got the answer and the identity

OpenStudy (anonymous):

I actually forgot the identity

OpenStudy (anonymous):

thanks for the help everyone! :)

OpenStudy (anonymous):

sorry I gave you some misinfo earlier. Was not thinking at all lol Goodluck :)

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