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trigonometry question(Click for the Question)
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\[\tan \theta + \cot \theta = 2 \] Find the value of :- \[\tan ^{2}\theta + \cot ^{2}\]
Hint: try squaring both sides
^
Do u mean (tan x + cot x )^2 ?/
Yes
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Nope i don't think so
Beacause (tan x + cot x )^2 = tan^2 x + 2 tanx . cot x + cot^2 x
(a+b)^2 types
Oh I compeletly forgot
disregard me lol
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no problem
well (tanx)(cotanx)= 1
That is actually what i mean, look at 2 tanx . cotx closely, you may notice something :)
so 2 is the answer
did you square both sides yet @openstudier
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yes
i got the answer and the identity
I actually forgot the identity
thanks for the help everyone! :)
sorry I gave you some misinfo earlier. Was not thinking at all lol Goodluck :)
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