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f(x)=[x]x^2 1≤ x <3
find dy/dx
explain the derivative of the [x] plz!!!
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OpenStudy (anonymous):
@ikram002p @ganeshie8
OpenStudy (ikram002p):
u wanna the derivative of [x]
or the derevative of f(x) ?
OpenStudy (anonymous):
derivative of f(x)
OpenStudy (anonymous):
i know that the deravative of [x] = 0 right ?
OpenStudy (ikram002p):
right !
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OpenStudy (anonymous):
so what's the derivative of f(x)
OpenStudy (ikram002p):
so u have f(x)=[x]x^2
f'(x)=[x]' x^2 + [x] (x^2)'
right ?
OpenStudy (ikram002p):
f'(x)=0+2[x]x
got it nw ?
OpenStudy (anonymous):
yep and it will be
2x[x] right ?
OpenStudy (ikram002p):
ur correct !
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OpenStudy (anonymous):
r u متأكدة ؟
OpenStudy (anonymous):
i used to find the derivative like that but someone told me that it's wrong o.O
OpenStudy (ikram002p):
and u also can explain it more
[x] = 1 , x<=1
[x]=2 , 1<x<2
[x]=3 , 2<x<3
so..
f'(x)=2[x] x
so,,, the rest u know
f'(x) = 2x , x=1
f'(x)=4x , 1<x<=2
f'(x)=6x , 2<x<=3
OpenStudy (ikram002p):
واضح :P
OpenStudy (anonymous):
واضح بس الحل الاول يختلف عن الحل الثاني
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OpenStudy (ikram002p):
la nafs el7al , entabeh mnee7 !
ana 2sta5damet f'(x)=2[x]x men al7al al2awal
bel 7al 2lthanee ana bass 3edet ta3reef [x] !
fa jawabak mosh 3'ala6 XD
laken fe nas bet7eb 2lfalsafeh XD
OpenStudy (anonymous):
XD lol !!!
OpenStudy (anonymous):
thanx alot
OpenStudy (ikram002p):
huh , but u got it ?
OpenStudy (ikram002p):
u know ur wlc any time ^^
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