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Mathematics 6 Online
OpenStudy (anonymous):

Help f(x)=[x]x^2 1≤ x <3 find dy/dx explain the derivative of the [x] plz!!!

OpenStudy (anonymous):

@ikram002p @ganeshie8

OpenStudy (ikram002p):

u wanna the derivative of [x] or the derevative of f(x) ?

OpenStudy (anonymous):

derivative of f(x)

OpenStudy (anonymous):

i know that the deravative of [x] = 0 right ?

OpenStudy (ikram002p):

right !

OpenStudy (anonymous):

so what's the derivative of f(x)

OpenStudy (ikram002p):

so u have f(x)=[x]x^2 f'(x)=[x]' x^2 + [x] (x^2)' right ?

OpenStudy (ikram002p):

f'(x)=0+2[x]x got it nw ?

OpenStudy (anonymous):

yep and it will be 2x[x] right ?

OpenStudy (ikram002p):

ur correct !

OpenStudy (anonymous):

r u متأكدة ؟

OpenStudy (anonymous):

i used to find the derivative like that but someone told me that it's wrong o.O

OpenStudy (ikram002p):

and u also can explain it more [x] = 1 , x<=1 [x]=2 , 1<x<2 [x]=3 , 2<x<3 so.. f'(x)=2[x] x so,,, the rest u know f'(x) = 2x , x=1 f'(x)=4x , 1<x<=2 f'(x)=6x , 2<x<=3

OpenStudy (ikram002p):

واضح :P

OpenStudy (anonymous):

واضح بس الحل الاول يختلف عن الحل الثاني

OpenStudy (ikram002p):

la nafs el7al , entabeh mnee7 ! ana 2sta5damet f'(x)=2[x]x men al7al al2awal bel 7al 2lthanee ana bass 3edet ta3reef [x] ! fa jawabak mosh 3'ala6 XD laken fe nas bet7eb 2lfalsafeh XD

OpenStudy (anonymous):

XD lol !!!

OpenStudy (anonymous):

thanx alot

OpenStudy (ikram002p):

huh , but u got it ?

OpenStudy (ikram002p):

u know ur wlc any time ^^

OpenStudy (anonymous):

yeah i got it :)

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