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what is the area of the trapezoid? I got 207yd2
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You are given two "lengths" for this trap.: one is 8 yd., the other 19 yd. Find their average: (8+19)/2. Multiply that by the height of the trap. (9 yd). The resulting product is the answer you wanted.
\[area=\frac{ \sum of \parallel sides }{ 2 }\times difference \between \parallel sides.\]
The following formula tells us the same thing, symbolically:\[A _{trapezoid}=\frac{ L _{1}+L _{2} }{ 2 }*h\] where h is the height of the trap. and L-sub-1 and L-sub-2 are the two different lengths. Substitute the given values and find the Area.
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The reason @mathmale's formula works is that it finds the area of the rectangle that would result if you straightened up the ends: |dw:1395608237610:dw|
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