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The interior angles of a polygon equal 360°. How many sides does this polygon have?
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A 3 B 4 C 6
The sum of the interior angles of an n-sided polygon is \[(n-2)*180^\circ\]
Solve for n S = 180(n-2) 360 = 180(n-2)
For a triangle, we have \(n=3\), so the sum of the interior angles of a triangle is \((3-2)*180^\circ = 180^\circ\) and I'm sure you know that to be true, even if you are unaware of the formula.
then what
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Well, as Jim said, solve \[360 = (n-2)*180\]for \(n\)
Or think of what regular polygon has 4 sides instead of 3, and what its angles add up to...
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