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Find to the nearest tenth, the perimeter of triangle ABC if A=(2,6) B=(5,10) C=(0,13)
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Graph the points
then calculate the units from each point
since there is 3 sides. Then add three sides.
the distance between two points (x1,y1) and (x2,y2) is given by \[d = \sqrt{(x2-x1)^2 + (y2-y1)^2}\] so you have to calculate AB, AC and BC and add them up
use distance formula to find the distance between two points
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ok thanks!
any time :)
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