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Mathematics 21 Online
OpenStudy (anonymous):

verify; sin2x+sinxcosx=3sinxcosx

mathslover (mathslover):

Subtract both sides by sinxcosx Can you tell me what would you get?

OpenStudy (anonymous):

sin2x=3

OpenStudy (anonymous):

we have sin2x=2sinxcosx so the right side will be 2sinxcosx+sinxcosx=3sinxcosx=left side

OpenStudy (anonymous):

got it ?

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