Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Can Anyone Please Help Me?

OpenStudy (anonymous):

rvc (rvc):

a^2+b^2=c^2

OpenStudy (anonymous):

Use Pythagora Theorem to solve the given problems...

rvc (rvc):

now try solving we will help u

OpenStudy (anonymous):

\[\huge a^2+b^2 = c^2\]

OpenStudy (anonymous):

what do i do draw the triangle and put the nnumbers it gives me in or idk

rvc (rvc):

substitute the given values

OpenStudy (anonymous):

Let us solve the first problem, a= 20, b= 5 \[\huge 20^2+ 25^2 = c^2\] \[\huge \rightarrow 400+ 625 = c^2\] \[\huge c^2 = 1025 \rightarrow c= \sqrt {1025} \rightarrow c= 32.01\]

OpenStudy (anonymous):

Similarly you can solve other problems as well..

OpenStudy (anonymous):

nevermind i dont evenn know what to do. Like do i have to do that for evey problem and do i draw a triangle and... idk nevermind

rvc (rvc):

3 ans 13 25+144=c^2 169=c^2 c=13 got it?

OpenStudy (anonymous):

im sorry i hate math and instead of waisting your guys time ill prolly just confuse my self u kno

rvc (rvc):

dr square a then square b add them then take square root on both sides its same 4 all sum @Monica

rvc (rvc):

@Monica75

OpenStudy (anonymous):

thank u guys so much

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!