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OpenStudy (anonymous):
Can Anyone Please Help Me?
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OpenStudy (anonymous):
rvc (rvc):
a^2+b^2=c^2
OpenStudy (anonymous):
Use Pythagora Theorem to solve the given problems...
rvc (rvc):
now try solving we will help u
OpenStudy (anonymous):
\[\huge a^2+b^2 = c^2\]
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OpenStudy (anonymous):
what do i do draw the triangle and put the nnumbers it gives me in or idk
rvc (rvc):
substitute the given values
OpenStudy (anonymous):
Let us solve the first problem,
a= 20, b= 5
\[\huge 20^2+ 25^2 = c^2\]
\[\huge \rightarrow 400+ 625 = c^2\]
\[\huge c^2 = 1025 \rightarrow c= \sqrt {1025} \rightarrow c= 32.01\]
OpenStudy (anonymous):
Similarly you can solve other problems as well..
OpenStudy (anonymous):
nevermind i dont evenn know what to do. Like do i have to do that for evey problem and do i draw a triangle and... idk nevermind
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rvc (rvc):
3 ans 13
25+144=c^2
169=c^2
c=13
got it?
OpenStudy (anonymous):
im sorry i hate math and instead of waisting your guys time ill prolly just confuse my self u kno
rvc (rvc):
dr square a then square b
add them
then take square root on both sides
its same 4 all sum
@Monica
rvc (rvc):
@Monica75
OpenStudy (anonymous):
thank u guys so much
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