Question

write the given equation in exponential form.
log 3 1/9 = -2? show work

Answer 1

\[\log_{a}x=y,a ^{y}=x\]

Answer 2

show work @surjithayer

Answer 3

@surjithayer

Answer 4

\[\log_{3} \frac{ 1 }{ 9 }=x (say)\]
\[3^x=\frac{ 1 }{ 9 }=\frac{ 1 }{ 3^2 }=1*3^{-2}\]
\[3^x=3^{-2},x=-2\]

Answer 5

so whats the answer? @surjithayer

Answer 6

Answer is
\[3^{-2}=\frac{ 1 }{ 9 }\]