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Which of the following points is in the solution set of y < x2 - 2x - 8? (-2, -1) (0, -2) (4, 0)
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\[y<x ^{2}-2x-8 \] ?
that is the equation. which point is in that solution set?
you have to factor out
(x- )(x+ )
just put these values in your equation.....
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and then you'll be able to find the solution set (or roots)
try out and i'll help you out
like (4,0) x=4 and y=0 0<4^2-2*4-8 0<16-8-8 0<0 not true so not the ans like this try other values
Ok. Thank you!
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