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evaluate the logarithmic expression log5 1/125? show work
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@gorv
\[\log_{a}a \]=1
when base and number are same log =1
\[\log_{5}1-\log_{5}125 \]
log1=0 0-log5 (5*5*5)=-log5*5^3=-3*log5 5=-3*1=-3
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why is it -3 instead of 3? @gorv
u knw??? log(a/b)=loga -logb
@ralph123
okay thanks @gorv
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