Question

triangle ABC has vertices A(2,0) B(6,7) and c (0,0). Which is the longest side of the triangle?

Answer 1

\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&({\color{red}{ 2}}\quad ,&{\color{blue}{ 0}})\quad B&({\color{red}{ 6}}\quad ,&{\color{blue}{ 7}})\\
B&({\color{red}{ 6}}\quad ,&{\color{blue}{ 7}})\quad C&({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}})\\
C&({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}})\quad A&({\color{red}{ 2}}\quad ,&{\color{blue}{ 0}})
\end{array}\qquad
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)