Question

F(x)=x^2-4/x+2


What is the domain and the vertical asymptote?

Answer 1

the domain is everything except where \(x+2=0\) i.e at \(x=-2\)

Answer 2

Oh ok that what I got too as my answer

Answer 3

there are no vertical asymptotes,
factor and cancel and you see
\[\frac{x^2-4}{x+2}=\frac{(x+2)(x-2)}{x+2}=x-2\]