Question

A projectile of mass 0.863 kg is shot straight up with an initial speed of 21.5 m/s. (a) How high would it go if there were no air resistance?

Answer 1

\[H= u ^{2}Sin ^{2}\theta \div 2g\] so here, \[Sin \theta \]=1 hence \[H=u ^{2}\div2g\] so 21.5x21.5/2x9.8