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A 14kg rock starting from rest free falls through a distance of 5.0m with no air resistance find the momentum change of the rock caused by it's fall& the resulting change in the magnitude of earths velocity. Earths mass is 6.0 × 10 24^ kg. Assume the rock eartg system is closed
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Rock velocity will be obtained from (1/2) m v^2 = m g h Momentum will be conserved, so rock gains m v and earth loses m v = (M)(change in Earth's velocity), which will be tiny velocity change when calculated
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