Question

Please Help!

Answer 1

Write a quadratic function in standard form for the parabola that passes
through the points (−1, −1), (0, −3), (1, 3).

Answer 2

\[y=ax^2+bx+c\]since \((0,-3)\) is on the graph, you know
\[c=-3\]

Answer 3

y=ax^2+bx+c
plug the values and find the values of a,b,c

Answer 4

then since \((-1,-1)\) is on the graph, you know
\[y=a(-1)^2+b(-1)-3=-1\]i.e. \[a-b-3=-1\\a-b=2\]

Answer 5

and since \((1,2)\) is on the graph you have
\[y=a(1)^2+b(1)-3=2\] or
\[a+b-3=2\\a+b=5\]

Answer 6

solve \[a-b=2\\a+b=5\] for \(a\) and \(b\)

Answer 7

or just cheat
http://www.wolframalpha.com/input/?i=quadratic+%28%E2%88%921%2C+%E2%88%921%29%2C+%280%2C+%E2%88%923%29%2C+%281%2C+3%29

Answer 8

@satellite73 thank you so much for your help :)

Answer 9

yw