Question

MEDAL TO BEST ANSWER!!!

x2 - 8x + 12
Factor this quadratic and show all work

4x2 - 6x + 2 = 0
Solve for x and show all work

Answer 1

Please help!!!!!

Answer 2

so you always have to think like this: what are the number added and give the middle (-8x) and also the product gives 12. can you think of any?

Answer 3

for the first one be (x-4)(x-3)? @Supenova

Answer 4

that will give you x2-7x+12

Answer 5

does -4 X (-3)= 12?

Answer 6

and now u can try to do the next one

Answer 7

yes. a negative times a negative equals a positive @hello1213

Answer 8

yes

Answer 9

but what is ur answer?

Answer 10

it has to be like this 4x2-4x-2x+2 . u see now u can factor

Answer 11

by distributive property

Answer 12

4x(x-1)-2(x-1)
so u have (4x-2)(x-1)

Answer 13

x2 -8x +12

break this down to
x2 -6x -2x +12 ( think of two negative numbers which multiply to give 12 and add to give -8, which in this case are -6 and -2)

taking like terms out :
x(x-6) -2(x-6)

you see that the terms in brackets are the same
therefore :

(x-2)(x-6)

Answer 14

4x-2 and x-1

Answer 15

u are close

Answer 16

and on the first one Ralph's answer is right

Answer 17

u r right too @smileandcanter

Answer 18

when u factor it you should have x-2 and x-6. mulitplying these two should give u x2-8x+12

Answer 19

4x(x-1)-2(x-1)
take the like terms and common take only one common factor of (x-1)
(4x-2)(x-1)

Answer 20

for the second one :

4x2 -6x +2 =0
multiply the first and last constants together ( i.e multiply 4 and 2)
The product is 8. Think of two numbers which multiply to give you 8 and add up to give you the middle constant (-6).
That would be -4 and -2

so rewrite the equation :

4x2 -4x -2x +2 =0

factorize:

4x(x-1) -2(x-1) =0

(4x-2)(x-1)=0

one of the terms has to be zero if the product of the terms is zero.

therefore
4x-2=0 or x-1=0

so, x=0.5 or x=1