Question

(1+csc/sec)-cot=cos

Answer 1

$$\csc x = \frac 1{\sin x}$$
$$\sec x = \frac 1{\cos x}$$
$$\cot x = \frac 1{\tan x}$$
Can you substitute these values in?

Answer 2

to make the algebra simpler, put \(a=\cos(x)\) and \(b=\sin(x)\) then show

\[1+\frac{\frac{1}{b}}{\frac{1}{a}}-\frac{a}{b}=a\]

Answer 3

actually, it is not true
maybe i read it wrong