Diagram 2 shows the straight line \frac{ x }{ 6 } + \frac{ y }{ 8 } = 1 cuts the y axis at D and the x axis at C. ABCD is a kite. The diagonal AC cuts the diagonal DB in the ratio 3:1.
Calculate the distance of DC. Hence find the coordinate of point A

Question

Diagram 2 shows the straight line \frac{ x }{ 6 } + \frac{ y }{ 8 } = 1 cuts the y axis at D and the x axis at C. ABCD is a kite. The diagonal AC cuts the diagonal DB in the ratio 3:1. 
Calculate the distance of DC. Hence find the coordinate of point A

anonymous · Answer

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anonymous · Answer

anyone here can help me? @ganeshie8 @ShadowLegendX @mathslover

mathslover · Answer

First step would be to simplify : $\cfrac{x}{6} + \cfrac{y}{8} = 1 $

anonymous · Answer

idk,show me how

anonymous · Answer

I only know 6 is x intercept. and 8 is  y intercept. and 1 is gradient maybe