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solve the differential equation: dy/ dx = (6x^2) / (y(1+x^2))
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\[ydy=\frac{ 6x^2 }{ 1+x^2 }dx\]
\[\int\limits_{}^{}ydy = 6 \int\limits_{}^{}\frac{ (x^2 +1) -1 }{ 1+x^2 }\]
do you know how to get the answers in ln? the options are 1. y = lnI1+x^3L +c 2. y^2 = -4lnI1+x^3I +c 3. y^2 = 4 ln I 1+x^2I +k where k = 2c
\[\int\limits_{}^{} y dy = 6 \int\limits_{}^{} dx - \int\limits_{}^{}\frac{ 1 }{ 1+x^2 } dx\]
\[y^2 = x - tanx + c\]
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actually i dont know how to solve it in ln, sorry !!
well what if you derive each answer ??
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