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how many sqrt(2)'s are there ?
\[2\sqrt{8}=2\sqrt{4\times2}=2\sqrt{4}\sqrt{2}=4\sqrt{2}\]
So A
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nope, answer is \(\large 8\sqrt{2}\)
O! well thank you guys
\(\large 4 \sqrt{2} + 7\sqrt{2} - 3\sqrt{2}\) \(\large 11\sqrt{2} - 3\sqrt{2}\) \(\large 8\sqrt{2} \)
^^just add the like terms
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