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Solve and Check. 3^2x-1 = 3^x+2
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\(3^{2x-1}=3^{x+2}\) take log base 3 of both sides \(\log_3(3^{2x-1})=\log_3(3^{x+2})\implies2x-1=x+2\) solve for x
Oh, ok same bases now solve the exponents. I got this far. I'm a little confused about having x on both sides...do I bring x to one side?
yes \(2x-1=x+2\\2x-1-x=2\\x-1=2\\x=3\)
Ok, thank you so much! I got it now!
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