Question

Another absolute value question?
Instead of just answering it, could you also explain? thanks. <3

|3d + 5| < 2

Answer 1

\[\left| x-a \right|<b,-b<x-a<b\]

Answer 2

value of 3d+5 lies between -2 and 2

Answer 3

the absolute is treated as the root of (the equation^2)
so |3d + 5| is treated as {\[\sqrt{(3d + 5)^2}\]}
so it has both a negative a positive value : \[\pm (3d + 5)\]
so you should plug in both negative and positive values