Question

what is the conic form of this ?: y = 4x^2 - 8x + 1

Answer 1

this is the standard form of a quadratic, Ax^2+Bx+C, the graph(or conic form) is a parabola

Answer 2

what? to get the conic form the eqaution is (y = 1/(4p)(x - h)2 + k) what is p?

Answer 3

@lucaz

Answer 4

oh, okay, you wanted to convert the equation

Answer 5

yes

Answer 6

@lucaz ?

Answer 7

first you need the vertex form y=4(x-1)^2-3
then convert to
y+3=4(x-1)^2
(y+3)/4=(x-1)^2