Question

How do you solve this quadratic equation ?
(2x-1)(3x-1) = 0

Can you please explain it to me...?

Answer 1

Is that 2x -1?

Answer 2

1/2 and 1/3

Answer 3

Okay... add the 1s to the zero.

1 = 2x

1 = 3x

Divide each side by three, and you get:

x = 1/2 and x = 1/3.

Answer 4

ohhhh, okay. thanks (:
can you help me with this one too ?

3x^2 + 12x + 9 = 0

Answer 5

Find two numbers that have a product of 27 (9*3) and a sum of 12.

3x^2 + 9x + 3x + 9 = 0

Pull out the GCF:

3x(x + 3) + 3(x + 3) = 0

(3x + 3)(x + 3) = 0

x = -3

3x = -3
x = -1

x = -1 and x = -3.

Answer 6

thankssss

Answer 7

You're welcome.