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Simplify the following expression. 5y(7y - 6) + 27y 35y2 - 3y 35y2 + 27y - 6 97y - 6 35y2 + 3y
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\[5y(7y-6)+27y\]\[=35y^2-30y+27y\]\[=35y^2-3y\]\[=y(35y-3)\]
Alright, you would be exactly correct except for your +3, in your work, when you exapdn 5y(7y-6) you get 35y^2-30y. Then all you have to do is add +25 to -30. Then you get 35y^2-3
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