Question

MEDALS!!!
The function f(x) = 582(7)^x represents the growth of a mosquito population every year in a remote swamp. Troy wants to manipulate the formula to an equivalent form that calculates every 2 months, not every year. Which function is correct for Troy's purposes?

Answer 1

f(x) = 582(7 to the one sixth power)6x

f(x) = 52(7)x

f(x) = 582(712)the x over 12 power

f(x) = 5852(7)x

Answer 2

f(x) = 582(7 to the one sixth power)^6x

f(x) = 52(7)^x

f(x) = 582(7^12)^x/12

f(x) = 5852(7)^x

Answer 3

Help please

Answer 4

@sourwing help again!

Answer 5

anyone!

Answer 6

@ganeshie8

Answer 7

@RadEn

Answer 8

f(x) = 582(7 1/6)12x

Answer 9

THAN YOU SO MUCH!
Can you help me with another?

Answer 10

Tag me in it c:

Answer 11

Wait thats not an answer choice!

Answer 12

ugh let me resolve

Answer 13

can you post a screenshot of the problem?

Answer 14

I still think that A would work... I'm not 100% sure, though :-/

Answer 15

uh oh haha
ok Ill go with that!
Is there a way to test each one?

Answer 16

Not really :( That problem is such a silly one, it makes no sense...what does 582 have to do with a year or whatever? You're not adding it (so it's not the original amount), you're multiplying it. Sorry I couldn't help with that one...

here's a graph for your other problem :)

Answer 17

Thanks so much!

Answer 18

No problem c: