Question

find dy/dx when y=0 if x cosy - sinx - 2 = 0

Answer 1

1/ isolate y
2/ take differential of y
3/ dat sit

Answer 2

would you mind showing me how to isolate y? im not sure how to do that

Answer 3

differentiate w.r.t. x
\[x(-\sin y)\frac{ dy }{ dx }+1*\cos y-\cos x-0=0\]
\[\frac{ dy }{dx }=?\]

Answer 4

\[\frac{ -\cos x }{ x \sin y }\]

Answer 5

\[\frac{ dy }{dx }=\frac{ \cos y-\cos x }{x \sin y }\]

Answer 6

Let me try once
xcos y - sinx -2 =0
xcos y = 2 + sinx
cos y = \(\dfrac{2+sinx}{x}\)
y = arcos \(\dfrac{2+sinx}{x}\)
now, take derivative the right hand side