Question

sin3x-cos2x

Answer 1

What do you have to do? Solving, verifying, developing?

Answer 2

Solving sin 3x - cos 2x = 0 by the equation (1)
sin 3x = cos 2x = sin (pi/2 - 2x) and sin 3x = sin (Pi - Pi/2 + x)
a) 3x = Pi/2 - 2x -> 5x = Pi/2 -> x = Pi/10
b) sin 3x = sin (Pi - Pi/2 + 2x) -> 3x = Pi/2 + 2x -> x = Pi/2
You may check the answers of the equation (1) by replacing x by its 2 values.