Question

How to factor (2x^2-9x-5). Preferably not the answer, simply an explanation.

Answer 1

2x^2 + 9x - 5 = 0
(2x -1)(x+5) = 0
2x - 1 = 0 x+5 = 0
x = 1/2 x=-5

Answer 2

How does multiplying a by c get rid of a Ventricate?

Answer 3

sorry I meant multiply 2 to 5, so you would have x^2- 9x-10, but when you factor you add the coefficient 2 that you multiplied at first resulting in (2x-10) (2x-1) and solve from there. Sorry for the super late reply!