Question

Angles JNH and ANE measure ____ degrees. (Hint: The measure of angles formed by a chord-chord pair is half the sum of the intercepted arcs.)
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Answer 1

Someone help?

Answer 2

angle JNH = 1/2( arc JIH + arc ACE ).
Yet to figure out how to find arc JIH + arc ACE.

Answer 3

Oh, the points A, B, C, ...L on the outermost circle are 12 vertices forming a 12-sided polygon. So each side makes an angle of 360/12 = 30 degrees at the center.
Arc JIH covers 2 sides out of 12 and so the arc JIH makes 2 * 30 = 60 degrees.
Arc ACE covers 4 sides out of 12 and so the arc ACE makes 4 * 30 = 120 degrees.

Angle JNH = 1/2( arc JIH + arc ACE ) = 1/2 (60 + 120) = 1/2 * 180 = 90 degrees.