Question

Help please!!

Answer 1

\[<MNL=<KNL\]

Answer 2

\[2y + 23 = 33 \rightarrow 2y = 10 \rightarrow y =5\]

Answer 3

A.23
B.33
C.55
D.57

Answer 4

What is the question?

Answer 5

Given that L is equidistant from M and K, find m<KLN

Answer 6

A.23
B.33
C.55
D.57

Answer 7

Angles in a right-angled triangle equal 90

Answer 8

Since we know that <KNL = <MNL = 33 then, we can say <KLN = 90 - 33 = 57 degrees

Answer 9

How about "k" in the problem What does k do?

Answer 10

Don't get you